Linearly dependent and independent rows
α1s1 + α2s2 + ... + αlsl
Solution. Form a linear combination of these rows
α1{2 5} + α2{4 10}
Let us find for what values of α1, α2 the linear combination is equal to the zero row
α1{2 5} + α2{4 10} = {0 0}
This equation is equivalent to the following system of equations:
2α1 + 4α2 = 0 | |
5α1 + 10α2 = 0 |
Divide the first equation by 2, and the second equation by 5:
α1 + 2α2 = 0 | |
α1 + 2α2 = 0 |
The solution of this system may be any number α1 and α2 such that: α1 = -2α2, for example, α2 = 1, α1 = -2, and this means that the rows s1 and s2 are linearly dependent.
Solution. Form a linear combination of these rows
α1{2 5 1} + α2{4 10 0}
Let us find for what values of α1, α2 the linear combination is equal to the zero row
α1{2 5 0} + α2{4 10 0} = {0 0 0}
This equation is equivalent to the following system of equations:
2α1 + 4α2 = 0 | |
5α1 + 10α2 = 0 | |
α1 + 0α2 = 0 |
From the third equation gives α1 = 0. Substituting this value in the first and second equation:
2·0 + 4α2 = 0 | => | 4α2 = 0 | => | α2 = 0 | |||
5·0 + 10α2 = 0 | 10α2 = 0 | α2 = 0 | |||||
α1 = 0 | α1 = 0 | α1 = 0 |
So as a linear combination of rows is equal to zero only when α1 = 0 and α2 = 0, the rows are linearly independent.
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